Hey, I have 2 tables in PostgreSql:
1 - documents: id, title
2 - updates: id, document_id, date
and some data:
documents:
| 1 | Test Title |
updates:
| 1 | 1 | 2006-01-01 |
| 2 | 1 | 2007-01-01 |
| 3 | 1 | 2008-01-01 |
So All updates are pointing to the same document, but all with different dates for the updates.
What I am trying to do is to do a select from the documents table, but also include the latest update based on the date.
How should a query like this look like? This is the one I currently have, but I am listing all updates, and not the latest one as the one I need:
SELECT * FROM documents,updates WHERE documents.id=1 AND documents.id=updates.document_id ORDER BY date
To include; The reason I need this in the query is that I want to order by the date from the updates template!
Edit: This script is heavily simplified, so I should be able to create a query that returns any number of results, but including the latest updated date. I was thinking of using a inner join or left join or s开发者_高级运维omething like that!?
Use PostgreSQL
extension DISTINCT ON
:
SELECT DISTINCT ON (documents.id) *
FROM document
JOIN updates
ON updates.document_id = document_id
ORDER BY
documents.id, updates.date DESC
This will take the first row from each document.id
cluster in ORDER BY
order.
Test script to check:
SELECT DISTINCT ON (documents.id) *
FROM (
VALUES
(1, 'Test Title'),
(2, 'Test Title 2')
) documents (id, title)
JOIN (
VALUES
(1, 1, '2006-01-01'::DATE),
(2, 1, '2007-01-01'::DATE),
(3, 1, '2008-01-01'::DATE),
(4, 2, '2009-01-01'::DATE),
(5, 2, '2010-01-01'::DATE)
) updates (id, document_id, date)
ON updates.document_id = documents.id
ORDER BY
documents.id, updates.date DESC
You may create a derived table which contains only the most recent "updates" records per document_id, and then join "documents" against that:
SELECT d.id, d.title, u.update_id, u."date"
FROM documents d
LEFT JOIN
-- JOIN "documents" against the most recent update per document_id
(
SELECT recent.document_id, id AS update_id, recent."date"
FROM updates
INNER JOIN
(SELECT document_id, MAX("date") AS "date" FROM updates GROUP BY 1) recent
ON updates.document_id = recent.document_id
WHERE
updates."date" = recent."date"
) u
ON d.id = u.document_id;
This will handle "un-updated" documents, like so:
pg=> select * from documents;
id | title
----+-------
1 | foo
2 | bar
3 | baz
(3 rows)
pg=> select * from updates;
id | document_id | date
----+-------------+------------
1 | 1 | 2009-10-30
2 | 1 | 2009-11-04
3 | 1 | 2009-11-07
4 | 2 | 2009-11-09
(4 rows)
pg=> SELECT d.id ...
id | title | update_id | date
----+-------+-----------+------------
1 | foo | 3 | 2009-11-07
2 | bar | 4 | 2009-11-09
3 | baz | |
(3 rows)
select *
from documents
left join updates
on updates.document_id=documents.id
and updates.date=(select max(date) from updates where document_id=documents.id)
where documents.id=?;
It has the some advantages over previous answers:
- you can write document_id only in one place which is convenient;
- you can omit where and you'll get a table of all documents and their latest updates;
- you can use more broad selection criteria, for example
where documents.id in (1,2,3)
.
You can also avoid a subselect using group by, but you'll have to list all fields of documents in group by clause:
select documents.*, max(date) as max_date
from documents
left join updates on documents.id=document_id
where documents.id=1
group by documents.id, title;
From the top of my head:
ORDER BY date DESC LIMIT 1
If you really want only id 1 your can use this query:
SELECT * FROM documents,updates
WHERE documents.id=1 AND updates.document_id=1
ORDER BY date DESC LIMIT 1
http://www.postgresql.org/docs/8.4/interactive/queries-limit.html
This should also work
SELECT * FROM documents, updates
WHERE documents.id=1 AND updates.document_id=1
AND updates.date = (SELECT MAX (date) From updates)
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