Creating pointer using #define

Is it possible to create pointer using #define?

Something like this:

#define *HEY

I'll u开发者_运维百科se it for something like this:

#define *HEY 2
...
int *s=HEY;

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No, asterisks aren't allowed in #define macro names.

Your example variable declaration wouldn't work anyway, because it doesn't contain the text *HEY, it only contains HEY, which doesn't match the defined macro name.

What's that code intended to do? Make a pointer that points to the number 2?

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defines are based completely on text replacement. They can only insert text everywhere you call the name. In your question you already made two mistakes.

You may not use * in the name of the macro if you want to call a macro you have to call it with the same name you defined it if * would have been legal, you sould also have called it with exactly that name *HEY

By the way. There is absolutely no secret functionality hidden somewhere in macro definitions.

#define HEY 2

simply replayces every HEY in your sourcecode with a 2 before compiling. Nothing else happens. You can replace everything you want to replace, even single opening braces if you want to.

#define OPEN (
...
cout << 2 * OPEN 3 + 4 ) << endl;

should work, even if is pretty useless