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PHP preg_match result

开发者 https://www.devze.com 2023-01-28 08:49 出处:网络
This PHP function working just fine: if (preg_match (\"/<(\\S+@\\S+\\w)>.*\\n?.*55[0-9]/i\",$body,$match)) {

This PHP function working just fine:

if (preg_match ("/<(\S+@\S+\w)>.*\n?.*55[0-9]/i",$body,$match)) {
echo "found!";
}

in

This message was created automatically by mail delivery software.

A message that you sent could not be delivered to one or more of its
recipients. This is a permanent error. The following address(es) failed:

xxx@hotmail.com
SMTP error from remote mail server after RCPT TO:<xxx@hotmail.com>:
host mx3.hotmail.com [65.54.188.72]: 550 Requested action not taken:
mailbox unavailable

But if I use the same php function in this case:

A message that you sent could not be delivered to one or more of its 
recipients. This is a permanent error. The following address(es) failed:

xxx@yahoo.com
SMTP error from remote mail server after end of data:
host d.mx.mail.yahoo.com [209.191.88.254]: 554 delivery error:
dd This user doesn't have a yahoo.com account (xxxd@yahoo.com) [0] -  mta1010.mail.mud.yahoo.com

The preg_match function does not give 开发者_运维问答any results. What am I doing wrong?


You are basically looking for a email addressing enclosed in < and >.

Your first input has it but the second input does not: It has no email id in < > hence you don't get a match.

Edit: (after your comment):

Looking at the 2 samples given by you the email id appears between the string failed: and the error code starting with 55. You can make use of the preg_match for this as:

if(preg_match('/failed:.*?(\b[A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,4}\b).*55[\d]/is',$str,$m)) {
       echo "Bounced email ".$m[1]."\n";
}

Ideone link


By default, preg_match doesn't support parsing of multiline string (String containing \n), so you gotta pass in extra parameter to match the whole string, which is m (multiline).

try

if (preg_match ("/<(\S+@\S+\w)>.*\n?.*55[0-9]/im",$body,$match)) {
echo "found!";
}
0

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