unix command - ignore "The" while sorting

I am listing directories and I would like to sort by name, but ignore leading "The", ie the output should be:

Apple
Th开发者_Python百科e Banana
Orange

and not

Apple
Orange
The Banana

What is the best way to do it?

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In fact I'm gonna put that in writing.

My suspicion is that the following will do what you want it to do:

ls -d * | sed 's/^The /\t/' | sort -b | sed 's/^\t/The /'

I'll explain. ls -d * lists all the directories. sed -r 's/^The /\t/' replaces all leading "The "s with tabs (a whitespace placeholder), sort -b sorts, ignoring leading whitespace (the tab), and sed 's/^\t/The /' replaces all those leading tabs with "The " again.

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ls | sed -e 's/^The \(.*\)/\1, The/' | sort | sed -e 's/\(.*\), The$/The \1/'

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This solution works, but is silly and won't work in every case (eg there are double spaces)

find . -type d | grep -o "[^./].*" | sed 's/^The/ /' | sort | sed 's/  /The /'