谭文清
2021-09-08 17:28
解：∠DOE = ∠DOC-∠EOC = 0.5∠BOC-0.5∠AOC = 0.5(∠BOC-∠AOC) =开发者_运维百科 0.5∠BOA = 0.5*90° = 45°
如图所示,已知角AOB=90°,角AOC是锐角,OD平分角BOC,OE...？
谭文清
2021-09-08 17:28
解：∠DOE = ∠DOC-∠EOC= 0.5∠BOC-0.5∠AOC= 0.5(∠BOC-∠AOC)=开发者_运维百科 0.5∠BOA= 0.5*90°= 45°
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![Interactive visualization of a graph in python [closed]](https://www.devze.com/res/2023/04-10/09/92d32fe8c0d22fb96bd6f6e8b7d1f457.gif)
加载中,请稍侯......
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