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How to add @xml:base to my .xml files?

开发者 https://www.devze.com 2023-01-27 21:55 出处:网络
I need a stylesheet to convert my docbook xml files so that they now include a xml:base element to my section tags.How do I go about doing that (since xml:base needs system and node info???)

I need a stylesheet to convert my docbook xml files so that they now include a xml:base element to my section tags. How do I go about doing that (since xml:base needs system and node info???)

Input:

<section xmlns="http://docbook.org/ns/docbook" xml:id="voidVisit" version="5">
<title>Void</title>

 <section>
  <title>Screenshot</title>
      <mediaobject>
          <imageobject>
              <imagedata fileref="screenshots/Dialog.png" />
          </imageobject>
      </mediaobject>
 </section>
</section>
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Output:

      ...
      <section xml:id="void" version="5"
           xml:base="file:/C:/Projects/my/proj/trunk/spec/module/components/void.xml">
     <title>Void</title>
     <section>
        <title>Screenshot</title>
        <mediaobject>
           <imageobject>
              <imagedata fileref="screenshots/Dialog.png"/>
           </imageobject>
        </mediaobject>
     </section>
     ...


In XSLT 2.0 (XPath 2.0) the functions static-base-uri() and base-uri() can be used for this purpose.

Here is a working example:

<xsl:stylesheet version="2.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes"/>
    <xsl:template match="/">
     <doc xml:base="{base-uri()}"/>
    </xsl:template>
</xsl:stylesheet>

when this transformation is applied, the wanted result is produced:

<doc xml:base="file:/C:/CVS-DDN/fxsl-xslt2/data/marrowtr.xml"/>

So, the complete transformation in your case is:

<xsl:stylesheet version="2.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:d="http://docbook.org/ns/docbook">
 <xsl:output omit-xml-declaration="yes"/>

    <xsl:template match="node()|@*">
      <xsl:copy>
         <xsl:apply-templates select="node()|@*"/>
      </xsl:copy>
    </xsl:template>

    <xsl:template match="/d:section">
     <xsl:copy>
       <xsl:attribute name="xml:base" select="base-uri(/)"/>
       <xsl:apply-templates select="node()|@*"/>
     </xsl:copy>
    </xsl:template>
</xsl:stylesheet>

In XSLT 1.0 the solution is to pass the base-uri as an external parameter (global xsl:param>) to the transformation.

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