I have created an SQL database using Java. I have a table created which has two columns, the first being a big integer which increments, the second I have tried defining it as a char, varchar and binary.
But I'm still not getting the desired functionality. Say I try and store a hex number 0a
into the char column and I get an error. I appended 0x
to the beginning and it seems to store, but when I print out the contents it is blank. Or in some cases I get characters such as '/' or 开发者_如何学Python'?'. I also tried using SQL explorer and it gives me the same result viewing the table,
My problem is I need to store an eight character hex string such as eb8d4ee6
.
Could someone please advise me of how this can be done?
See http://dev.mysql.com/doc/refman/5.5/en/hexadecimal-literals.html
MySQL supports hexadecimal values, written using X'val', x'val', or 0xval format, where val contains hexadecimal digits (0..9, A..F). Lettercase of the digits does not matter. For values written using X'val' or x'val' format, val must contain an even number of digits. For values written using 0xval syntax, values that contain an odd number of digits are treated as having an extra leading 0. For example, 0x0a and 0xaaa are interpreted as 0x0a and 0x0aaa.
In numeric contexts, hexadecimal values act like integers (64-bit precision). In string contexts, they act like binary strings, where each pair of hex digits is converted to a character:
You probably should store the Hex number in an integer column. You can then convert back to hex when selecting using the HEX()
function.
E.g.,
INSERT INTO MyTable (`MyIntegerColumn`) VALUES (0xeb8d4ee6);
You can use a Json column:
And use JSON.stringify(hex)
to insert and you can always get the result via select and compare too
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