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Java - output array without its formatting

开发者 https://www.devze.com 2023-01-27 16:38 出处:网络
I am writing an app that allows the user to create custom SQL queries with user input. I add the falue from each JTextFields to the array using

I am writing an app that allows the user to create custom SQL queries with user input.

I add the falue from each JTextFields to the array using

for(JTextField field : fields){
 if (!field.getText().equals("")){
   rows.add(field.getText());
 }
}

When i output an array it is wrapped in square brackets

[arVal1, arVal2, etc, etc]

So when i inser the array into the query string it looks like this:

INSERT INTO table ([arval1, arval2, arVal3]) VALUES ([bla, bla, bla])

When i run the query for some reason i get: ORA-00928: missing SELECT keyword error; but if i have a default string for the query like:

INSERT INTO table (arval1, arval2, arVal3) VALUES (bla, bla, bla)

it works fin开发者_Python百科e.

Im looking to get rid of the [] when outputting the array

Thank You


You shouldn't rely on the toString method of the array.

Using Guava, try Joiner.on(",").join(myArray);


If you cannot use Guava (but I recommend it :) )

StringBuilder builder = new StringBuilder();
builder.add("INSERT INTO table (");
for(int i=0; i<rows.length: rows){
   builder.add(row);
   if(i<rows.length -1){
      builder.add(",")
   }
}
builder.add(") VALUES (");
....

To complete, with Guava, it looks like this:

Joiner commaJoiner = Joiner.on(", ");
"INSERT INTO table (" + commaJoiner.join(rows) + " VALUES " + commaJoiner.join(values)


Maybe an overly complicated solution, but try overriding toString()

 ArrayList<String> rows = new ArrayList<String>()
    {
        public String toString()
        {
            StringBuffer retVal = new StringBuffer();
            for(int i = 0; i < size(); i++)
            {
                retVal.append(this.get(i));
                if(i < size() - 1)
                {
                    retVal.append(",");
                }
            }
            return retVal.toString();
        }
    };
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