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Default parameter for a list reference

开发者 https://www.devze.com 2023-01-27 15:55 出处:网络
In C++, how would I specify a default value for a list reference in a function? void fun( std::list<My_Object *> &the_list,

In C++, how would I specify a default value for a list reference in a function?

void fun(
  std::list<My_Object *> &the_list,
  int开发者_StackOverflow n = 4
) 


if it is a plain reference, the only thing you an default it to is a valid lvalue which probably is not available. But if it is a reference to const you could default it to an empty list like this:

void fun(
  std::list<My_Object *> const & the_list = std::list<My_Object *>(),
  int n = 4
) 

If you have a list named a, which is available at the declaration site, then like this

void fun(
      std::list<My_Object *> & the_list = a,
      int n = 4
    ) 

but be careful so that the a list is still "alive" when you call the function


In C++, how would I specify a default value for a list reference in a function?

I wouldn't, in your case. Either overload the function so that it can be called without a list, or take the argument per pointer, so that users can pass a NULL pointer.

I'd strongly prefer overloading.

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