XElement to get all sub-element node names and values

I'm thinking of an approach something like this. Please let me know if this can actually work this way: For Sample XML:

<Root>
  <Node>
    <SubEl1>abc</SubEl1>
    <SubEl2>def</SubEl2>
    <SubEl3>123</SubEl3>
    <SubEl4>456</SubEl4>      
  </Node>
</Root>

Want to go into <Node>, loop through check for the node/element name and get it's value. Something like this, say name is 'SubEl1' use 'abc' for task1, on seeing the element name is 'SubEl2' I do task2. All sub-elements have to be checked for!

Example (not working code):

 //looping through 'Node' children
        switch(SubElName for 'Node element) 
        {
          case : 'SubEl1' 
            //Do Task1 using the SubEl1's value/TextName ...
        开发者_StackOverflow中文版  case: 'SubEl2' 
           //Task2 ...
          ... 
          case: default //Do default task.....
        } 
    //end loop

If you can think of any other approach (XElement, XmlDocument, SelectNodes() etc., that will be appreciated too!

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For this task it looks like all you need to do is simply create a list/dictionary of the node name and the node value, you then can use that in your switch....

var list = from x in XElement.Load(**yourxmlfile**).Element("Node").Elements()
           select new
           {
              Name = x.Name,
              Value = (string)x
           };

now you have a list of Name, value pairs you can simply pass to your switch method.

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Haven't made a use of it yet but LINQ to XML looks like all kinds of awesome. Here are some links. MSDN Reference Hooked On LINQ

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use http://msdn.microsoft.com/de-de/library/bb342765.aspx to get all children and http://msdn.microsoft.com/de-de/library/system.xml.linq.xelement.name.aspx to check for the name.