When开发者_Python百科 we declare (example) List<T>
I can understand the declaration, but suppose I declare
IEnumerable<T<T1, T2>>
What did I actually declare?
Does it mean,
IEnumerable<T>
contains two generic types? (What is the way to use it?)Can I have deep nested level like
Person<T<T2<T3<P1,P2>>>>
?
Simple example will really helpful.
If you have a class
public class Pair<T1, T2> { ... }
then you can declare a method
IEnumerable<Pair<int, string>> GetPairs();
i.e. a method that returns an enumerable of pairs where each pair consists of an int and a string.
Usage:
foreach (Pair<int, string> pair in GetPairs()) { ... }
You can also deeply nest these:
IEnumerable<Pair<int, Pair<string, string>>> GetPairs();
i.e. a method that returns an enumerable of pairs where each pair consists of an int and a pair of two strings.
This works with generics as well:
IEnumerable<Pair<T1, T2>> GetPairs<T1, T2>();
i.e. a method that returns an enumerable of pairs where each pair consists of a T1 and a T2.
But you cannot do this:
IEnumerable<T<T1, T2>> GetGenericPairs<T, T1, T2>();
Unless you've actually got a generic type called T
, that won't work. You need a real type there, e.g.
IEnumerable<Dictionary<string, int>>
which is a sequence of Dictionary<string, int>
references.
But yes, you can nest generics a lot - and it becomes pretty unreadable:
List<Dictionary<List<IEnumerable<string>>, Dictionary<int, int>>> aargh = null;
The above example will not compile. But you can embed Generic types within one another with something like this:
IEnumerable<IEnumerable<int>>
Which would be an enumerable of an enumerable of ints (which would act as a jagged 2 dimensional array).
(1) You declared an IEnumerable
that enumerates objects of type T<T1, T2>
. For example, Hashtable<Int, String>
.
(2) Sure you can!
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