I don'开发者_JAVA百科t how to do the coding in jquery for checkbox
<p class="list">
<label for="chkSunday"><input type="checkbox" checked name="chkday" id="chkday0" value="0" />All days</label>
<label for="chkSunday"><input type="checkbox" name="chkday" id="chkday1" value="1" />Sunday</label>
<label for="chkMonday"><input type="checkbox" name="chkday" id="chkday2" value="2" />Monday</label>
<label for="chkTuesday"><input type="checkbox" name="chkday" id="chkday3" value="3" />Tuesday</label>
<label for="chkWednesday"><input type="checkbox" name="chkday" id="chkday4" value="4" />Wednesday</label>
<label for="chkThursday"><input type="checkbox" name="chkday" id="chkday5" value="5" />Thursday</label>
<label for="chkFriday"><input type="checkbox" name="chkday" id="chkday6" value="6" />Friday</label>
<label for="chkSaturday"><input type="checkbox" name="chkday" id="chkday7" value="7" />Saturday</label>
</p>
In above check boxes I have some use cases:
- Usecase 1
- User selected any of the day then "all" check box should uncheck
- Use case 2
- User unchecked all days then "all" check box should checked
I dont know how to handle this in jQuery.
I think this is what you're after:
$(".list :checkbox").change(function() {
if(this.id == "chkday0") $(".list :checkbox:gt(0)").attr("checked", false);
$("#chkday0").attr("checked", $(".list :checkbox:gt(0):checked").length == 0);
});
You can test it out here. What this is doing is rigging up a change
handler to every checkbox in that <p>
.
- If it's the first (all), clear all the other days.
- No matter which one it was, check the first if none others are selected (check All if no days).
Also note in the demo the <label>
elements changed...they had invalid for
attributes, and since they wrap the <input>
they go with, you can just remove the for
anyway.
This is pretty similar to @Nick's answer, but avoids some of the DOM selection. It assumes a static group of elements.
Example: http://jsfiddle.net/patrick_dw/7UwLU/
var $allBoxes = $('p.list input:checkbox').change(function() {
var $dayBoxes = $allBoxes.slice(1);
if ($allBoxes[0].checked) $dayBoxes.not(this).attr('checked', '');
$allBoxes[0].checked = !$dayBoxes.filter(':checked').length;
});
No need to change the accepted answer. Just showing another way.
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