How do I add a line break for read command?

 read -p "Please Enter a Message:" message

开发者_运维技巧How can I add a line break after Message:?

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Just looking for the exact same thing. You can use:

# -r and -e options are unrelated to the answer.
read -rep $'Please Enter a Message:\n' message

And it will work exactly as asked:

Please enter a Message:
_

Here is an extract from the bash manpage explaining it:

Words of the form $'string' are treated specially. The word expands to string, with backslash-escaped characters replaced as specified by the ANSI C standard. Backslash escape sequences, if present, are decoded as follows:

• (...)
• \n new line
• (...)

The expanded result is single-quoted, as if the dollar sign had not been present.

Took me a while to find out.

Note that single quotes and double quotes behave differently in this regard:

A double-quoted string preceded by a dollar sign ($) will cause the string to be translated according to the current locale. If the cur- rent locale is C or POSIX, the dollar sign is ignored. If the string is translated and replaced, the replacement is double-quoted.

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I like Huang F. Lei's answer, but if you don't like the literal line break, this works:

read -p "Please Enter a Message: `echo $'\n> '`" message

Shows:

Please Enter a Message:
> _

...where _ is where the cursor ends up. Note that since trailing newlines are usually dropped during command substitution, I've included the > afterward. But actually, your original question doesn't seem to want that prompt bit, so:

# Get a carriage return into `cr` -- there *has* to be a better way to do this
cr=`echo $'\n.'`
cr=${cr%.}

# Use it
read -p "Please Enter a Message: $cr" message

Shows

Please Enter a Message:
_

There has to be a better way, though.

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Here's an improvement on the accepted answer that doesn't require spawning a subshell:

read -p "Please Enter a Message:"$'\n' message

From the GNU Bash reference manual:

Words of the form $'string' are treated specially. The word expands to string, with backslash-escaped characters replaced as specified by the ANSI C standard.

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$ read -p "Please Enter a Message:
> " message
Please Enter a Message:

Typing a "newline" between ':' and '"' directly.

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Just to improve the answers of Huang F. Lei and of T.J. Crowder which I like (and added +1) .. You can use one of the following syntaxes too, which basically are the same, it depends on your taste (I prefer the first one):

read -p "$(echo -e 'Please Enter a Message: \n\b')" message
read -p "`echo -e 'Please Enter a Message: \n\b'`" message

which both will produce the following output:

Please Enter a Message: 
_

where _ is the cursor.
In case you need a newline in any part of the string but the end, you can use \n, for example

read -p "`echo -e '\nPlease Enter\na Message: '`" message

will produce

.
Please Enter
a Message: _

where . is a blank first new line and _ is the cursor.

Only to add a final trailing newline you have to use \n\b as in my first example

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From the bash manpage:

-p prompt
   Display prompt on standard error, without a trailing new-
   line, before attempting to read any input.  The prompt is
   displayed only if input is coming from a terminal.

So, not with read itself, and putting \n in the message string just echoes \n. The answer should be simple though - don't get read to display the prompt:

echo "Please Enter a Message:" 1>&2
read message

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read -p "$(printf 'Please Enter a Message:\n')" message

With printfyou can use \n for line breaks.

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read -p "Please Enter a Message:Return" message