operator precedence (void* before bool?)

When answering this question I made some research which really confuses me.

I noticed that two ifstreams that succesfully open are not equal but two ifstreams that fail are. At first i checked cplusplus.com. The operator ! returns the status of the badbit and failbit. I think that the opposite of this would still be to return the status of these two bits, but flipped.

• Wrong, because two succesful calls are not equal.

So then I figured it was an operator bool somewhere that would return something. So I tried to backtrack from ifstream and found the istream::operator bool(), which is returning _Ok.

• Still wrong however, this doesn't seem to be called at all (and couldn't be, since the two successful calls are still not equal).

So I changed my approach and checked the disassembly from Visual Studio. And what do I find?

if (file0 != file1) { doesn't call the operator bool(), but rather the operator void* () (or really __imp_std::ios_base::operator void *).

So the questions I have are..

• Shouldn't any operator bool () found be called before trying to casting it to pointer values?
• Is it some operator bool() I m开发者_如何学Cissed that in turn is calling the operator void* ?

• Is this some optimizing that I don't understand?

• Or am I completely wrong in that C++ actually thinks that void* is a better match than bool in this comparison?

---

1.) You cannot overload multiple times but with different return types. 2.) Yes, operator! returns the badbit/failbit, but operator! is something entirely different from operator!=, which is the one you are using.