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defining friend function within templated class

开发者 https://www.devze.com 2023-01-26 21:36 出处:网络
I use three different files to define a templated class. The class declaration is in a .h file, the implementation in a .cpp file and explicit instantiations are included in a .inc file.

I use three different files to define a templated class. The class declaration is in a .h file, the implementation in a .cpp file and explicit instantiations are included in a .inc file. I'm trying to define a friend function that it's able to access private data members of a templated class. As in the case of templated classes, the function will be defined, implemented, and instantiated in 3 separate files. When I try the call the function, I get the following error messages:

myclass.h:error: ‘doSomething’ is neither function nor member function; cannot be declared friend

myclass.h:error: expected ‘;’ before ‘<’ token

mymethod.h: error: ‘friend’ used outside of class

Does anybody has any suggestion on how to solve this issue? I tried to simplify the code below.

myclass.h

  template<class T>
  class MyClass{

      friend T doSomething<T>( MyClass<T> *, T, int);
      friend  MyClass<T> * doSomethingElse<T>( const MyClass<T> *, const MyClass<T> *);
      public:
               ...
      private:
         T *m_pMyMatrix;
  };

mymethod.h

#include <myclass.h>
template <class T> friend T doSomething( MyClass<T> *, T, int);
template <class T> MyClass<T>* doSomethingElse(const MyClass<T>*, const MyClass<T>*);

mymethod.cpp

#include <mymethod.h>
template <class T>
T doSomething( MyClass<T> * pData, T val, int index){
   // the actual code does sth. more complex than the code below.
   pData->m_pMyMatrix[index]+=val;
   return pData->m_pMyMatrix[index];
}

template <class T>
MyClass<T>* doSomethingElse(const MyClass<T> * pData1, const MyClass<T> * pData2){
   ...
   T res1 = doSomething(pData1, val1, index1);
   ...
}
#include "mymethod-impl.inc"

mymethod-impl.inc

template float doSomethi开发者_Go百科ng( MyClass<float> *, float, int);
template double doSomething( MyClass<double> *, double, int);

template MyClass<float>* doSomethingElse(const MyClass<float>*, const MyClass<float>*);
template MyClass<double>* doSomethingElse(const MyClass<double>*, const MyClass<double> *);


I think this should worK

template<class T>
class MyClass;

template <class T>
T doSomething( const MyClass<T> *, T, int);

template<class T>
class MyClass {
  friend T doSomething<T>( const MyClass<T> *, T, int);
public:
  ...
private:
  T *m_pMyMatrix;
};

That is, you need to declare the template before you can make it (or an instance thereof) a friend.


I think I solved this:

mymethod.h

template<class T> class MyClass;

template<class T> 
T doSomething<T>(const MyClass<T>* pData, T val, int index);

myclass.h

#include "mymethod.h"

template<class T>
class MyClass {
    friend T doSomething<T>(const MyClass<T>* pData, T val, int index);

public:
    // ...

private:
    T *m_pMyMatrix;
};

mymethod.cpp

#include "myclass.h"

template<class T>
T doSomething(const MyClass<T>* pData, T val, int index)
{
    pData->m_pMyMatrix[index]+=val;
    return pData->m_pMyMatrix[index];
}

template<> float doSomething( const MyClass<float> *, float, int);
template<> double doSomething( const MyClass<double> *, double, int);

In practice, only thing you need is to declare the template function before MyClass definition.

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