Not really a question but kind of a challenge..
I have this PHP function that I always use and now I need it in Javascript.
function formatBytes($bytes, $precisi开发者_StackOverflowon = 0) {
$units = array('b', 'KB', 'MB', 'GB', 'TB');
$bytes = max($bytes, 0);
$pow = floor(($bytes ? log($bytes) : 0) / log(1024));
$pow = min($pow, count($units) - 1);
$bytes /= pow(1024, $pow);
return round($bytes, $precision) . ' ' . $units[$pow];
}
EDIT: Thanks to the replies I came up with something shorter, but without precision (let me know if you have some second thoughts)
function format_bytes(size){
var base = Math.log(size) / Math.log(1024);
var suffixes = ['b', 'KB', 'MB', 'GB', 'TB' , 'PB' , 'EB'];
return Math.round(Math.pow(1024, base - Math.floor(base)), 0) + ' ' + suffixes[Math.floor(base)];
}
Think this is right, have not tested it:
Update: Had to fix it as there was no default for precision and I had a typo in the last line, now functional.
function formatBytes(bytes, precision) {
var units = ['b', 'KB', 'MB', 'GB', 'TB'];
var bytes = Math.max(bytes, 0);
var pow = Math.floor((bytes ? Math.log(bytes) : 0) / Math.log(1024));
pow = Math.min(pow, units.length - 1);
bytes = bytes / Math.pow(1024, pow);
precision = (typeof(precision) == 'number' ? precision : 0);
return (Math.round(bytes * Math.pow(10, precision)) / Math.pow(10, precision)) + ' ' + units[pow];
}
Tested:
function formatBytes(bytes, precision)
{
var units = ['b', 'KB', 'MB', 'GB', 'TB'];
bytes = Math.max(bytes, 0);
var pwr = Math.floor((bytes ? Math.log(bytes) : 0) / Math.log(1024));
pwr = Math.min(pwr, units.length - 1);
bytes /= Math.pow(1024, pwr);
return Math.round(bytes, precision) + ' ' + units[pwr];
}
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