Is there an STL/boost algorithm that will test if all the elements between two iterators match a given value? Or alternatively that a predicate returns true
for all of them?
i.e. something like
template<class InputIterator, class T>
InputIterator all_match (InputIterator first, InputIterator last, const T& value)
{
bool allMatch = true;
while(allMatch && first!=last开发者_开发问答)
allMatch = (value == *first++);
return allMatch;
}
Or
template <class InputIterator, class Predicate>
bool all_true (InputIterator first, InputIterator last, Predicate pred)
{
bool allTrue = true;
while (allTrue && first != last)
allTrue = pred(*first++);
return allTrue;
}
If you can negate the predicate you can use std::find / std::find_if and see if it returns the end element of your sequence. If not then it returns the one that does match.
You can adapt an function with std::not1 or std::not_equal_to so by doing combined with std::find_if you can indeed do so using STL without writing a loop.
bool allMatch = seq.end() == std::find_if( seq.begin(), seq.end(),
std::not_equal_to(val) );
bool allPass = seq.end() == std::find_if( seq.begin(), seq.end(),
std::not1(pred) );
C++11 introduces std::all_of
.
You could use std:find ord std::find_if to do this.
template <class T>
struct pred {
T t_;
pred(const T& value) : t_(value) {}
bool operator()(const T &t)
{
return t != t_;
}
};
if (e.cend() == std::find_if(c.cbegin(), c.cend(), pred<T>(value)))
print("all match value");
You can use std::equal
with the predicate. Something like:
using namespace std;
using namespace boost::lambda;
int main()
{
vector<int> a;
a.push_back(1);
a.push_back(1);
a.push_back(2);
a.push_back(2);
a.push_back(3);
bool allMatch = equal(a.begin(), a.begin() + 2, a.begin(), _1 == 1);
return 0;
}
Often you can just count them:
template<class FwdIterator, class T>
InputIterator all_match (FwdIterator first, FwdIterator last, const T& value)
{
return std::count(first, last, value) == std::distance(first, last);
}
Inefficient when the iterator isn't random, or when it returns false. Doesn't work for input iterators.
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