struc开发者_StackOverflow中文版t ethernet_header
{
u_char ether_dhost[ ETHER_ADDR_LEN];
u_char ether_shost[ETHER_ADDR_LEN];
u_short ether_type;
};
for(i = 0;i <6; i++)
printf("dest ether:%x",ethernet->ether_dhost);
How to print the Ethernet address in proper readable form with spaces after each byte? The o/p I get is in hex. Here Ethernet is the pointer to the structure ethernet_header
.
How about:
printf("%02x:%02x:%02x:%02x:%02x:%02x",
(unsigned)ethernet->ether_dhost[0],
(unsigned)ethernet->ether_dhost[1],
(unsigned)ethernet->ether_dhost[2],
(unsigned)ethernet->ether_dhost[3],
(unsigned)ethernet->ether_dhost[4],
(unsigned)ethernet->ether_dhost[5]);
I think the best way would be to use ether_ntoa() which is available on just about any *nix operating system (available in net/ethernet.h). The following works quite well for me.
char *addr;
struct ether_addr host;
memcpy(&host, ethernet->ether_dhost, sizeof(host));
addr = ether_ntoa(&host);
Something like this should do it:
char mac[6 * 2 + 5 + 1];
for(size_t i = 0, pos = 0; i < sizeof ethernet->ether_dhost; i++)
{
if(i > 0)
mac[pos++] = ':';
sprintf(mac + pos, "%02x", (unsigned int) ethernet->ether_dhost[i] & 0xffu);
}
This also inserts colons between each byte, so the output will look like DE:AD:BE:EF:BA:BE
which is how MAC addresses are commonly formatted for Ethernet.
精彩评论