This code fails with an exception indicating invalid JSON:
var example = '{ "AKEY": undefined }';
jQuery.parseJSON(example);
I was able to fix it by replacing all undefineds with empty strings. Are 开发者_JAVA百科undefineds not part of JSON?
If you can wrap your head around this, the token undefined
is actually undefined.
Allow me to elaborate: even though JavaScript has a special primitive value called undefined, undefined
is not a JavaScript keyword nor does it have any special meaning. You can break code which tests for the existance of an object by comparing to undefined
by defining it.
var obj = { BKEY: 'I exist!' };
if (obj.AKEY == undefined) console.log ('no AKEY');
if (obj.BKEY == undefined) console.log ('should not happen');
undefined='uh oh';
if (obj.AKEY == undefined) console.log ('oops!'); // Logically, we want this to execute, but it will not!
if (obj.BKEY == undefined) console.log ('should not happen');
The only console output will be 'no AKEY'. After we've assigned to the global variable undefined
, obj.AKEY == undefined
becomes false because undefined != 'uh oh'
. obj.BKEY == undefined
still returns false, but only because we're lucky. If I had set obj.BKEY='uh oh'
, then obj.BKEY == undefined
would be true, even though it actually exists!
You probably want to explicity set AKEY
to null
. (By the way, null
is a keyword; null='uh oh'
throws an exception).
You could also simply omit AKEY
from your JSON, in which case you would find:
typeof(example.AKEY) == 'undefined'
(If you set AKEY
to null
, then typeof(example.AKEY) == 'object'
.)
The only real difference between setting to null and omitting is whether you want the key to appear in a foreach loop.
No, but null
is. RFC 4627 §2.1:
A JSON value MUST be an object, array, number, or string, or one of the following three literal names:
false null true
var example = '{ "AKEY": null }';
Correct. Undefined and functions are not represented in JSON. http://www.json.org/js.html
They're not permitted in JSON...look at the alternative and it's clear as to why:
var example = '{}';
var obj = jQuery.parseJSON(example);
obj.AKEY //undefined
If it's undefined
, when you go to access it, it's the same as the key not even being present. Since JSON's primary purpose is for transmitting data (otherwise the broader object literal syntax is fine)...it's better to leave it out altogether.
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