开发者

Wrapping stuff with jQuery

开发者 https://www.devze.com 2023-01-26 00:38 出处:网络
I need to get some list elements inside of wrapper div/span. This is h开发者_高级运维ow it is now:

I need to get some list elements inside of wrapper div/span. This is h开发者_高级运维ow it is now:

<ul>
<li>One</li>
<li>Two</li>
<li>Three</li>
<li>Four</li>
<li>Five</li>
<li>Six</li>
</ul>

What I need is something like this:

<ul>
<div class="wrapper">
<li>One</li>
<li>Two</li>
</div><div class="wrapper">
<li>Three</li>
<li>Four</li>
</div><div class="wrapper">
<li>Five</li>
<li>Six</li>
<div class="wrapper">
</ul>

Or that can be somthing like span. Doesnt really matter. BUt I need to wrap after every three li elements.


You can iterate over your elements and wrap them using .slice() and .wrapAll(), like this:

var lis = $("ul li");
for(var i = 0; i < lis.length; i+=3) {
  lis.slice(i, i+3).wrapAll('<li class="wrapper"><ul></ul></li>');
}

Since you said something like a <div>/<span> this will do the job, and give you valid HTML, like this:

<ul>
  <li class="wrapper">
    <ul>
      <li>One</li>
      <li>Two</li>
      <li>Three</li>
    </ul>
  </li>
  <li class="wrapper">
    <ul>
      <li>Four</li>
      <li>Five</li>
      <li>Six</li>
    </ul>
  </li>
</ul>

Your example showed every 2 elements, but your question text said every 3...I just picked 3 here, just adjust the number in the function and you're all set.


It is not valid HTML and it is wrong to do it - You cannot insert div inside list, but I will give for future reference the syntax of wrapping in jQuery:

$("JQUERYSELECTOR").wrap("<div class='wrapper'></div>");

The JQUERYSELECTOR should be whatever elements that you want to wrap i.e

#ul:nth-child(1)

for the first child of the list.

But again, wrapping div on list items is wrong.

0

精彩评论

暂无评论...
验证码 换一张
取 消