I need to search a string for any occurances of another string in PHP. I have some co开发者_JAVA技巧de that I've been playing with, but it doesn't seem to be working.
Here is my code:
while (list($key, $val) = each($keyword)) {
$pos = strpos($location, $val);
if($pos == false) {
echo "allow";
exit;
} else {
echo "deny";
exit;
}
}
I have tried some of the options below, but it still does not find the match. Here is what I'm searching:
I need to find:*
blah
In:
http://blah.com
Nothing seems to find it. The code works in regular sentences:
Today, the weather was very nice.
It will find any word from the sentence, but when it is all together (in a URL) it can't seem to find it.
When checking for boolean FALSE
in php, you need to use the ===
operator. Otherwise, when a string match is found at the 0
index position of a string, your if
condition will incorrectly evaluate to true
. This is mentioned explicitly in a big red box in the php docs for strpos()
.
Also, based on a comment you left under another answer, it appears as though you need to remove the exit
statement from the block that allows access.
Putting it all together, I imagine your code should look like this:
while (list($key, $val) = each($keyword)) {
$pos = strpos($location, $val);
if($pos === false) { // use === instead of ==
echo "allow";
} else {
echo "deny";
exit;
}
}
Update:
With the new information you've provided, I've rewritten the logic:
function isAllowed($location) {
$keywords = array('blah', 'another-restricted-word', 'yet-another-restricted-word');
foreach($keywords as $keyword) {
if (strpos($location, $keyword) !== FALSE) {
return false;
}
}
return true;
}
$location = 'http://blah.com/';
echo isAllowed($location) ? 'allow' : 'deny';
精彩评论