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Matching a list of words with a sentence

开发者 https://www.devze.com 2023-01-25 01:47 出处:网络
I have a list of \"bad\" words having around 450 words in it. I\'m trying to check the sentence for it with

I have a list of "bad" words having around 450 words in it.

I'm trying to check the sentence for it with

<?php
$sentence = "A quick brown fox jumps over the lazy dog";
foreach($words as $word) {
    $check  =   strstr($sentence,$word);
    i开发者_C百科f(!empty($check))
        return false;        
}
return true;
?>

Is there a faster and better approach to this?


You could try using a preg_split and array_intersect

<?php
$sentence = "A quick brown fox jumps over the lazy dog";
$sntce_wrds = preg_split('/\s+/', $sentence);
return count(array_intersect($sntnce_words, $words)) > 0;


I think preg_replace should fit your needs as well. Pass the $words array as the pattern and space as the replacement. Then match the result with the original string. For e.g

$newStr = preg_replace($words, '', $sentence);

if($newStr !== $sentence)
    return false;

return true;

Let know if this helps.

Edit: As pointed out by stillstanding, the words in the $words array need to be valid regexes. So this method would only work if the words are changed to patterns like "one" to "/one/".

Edit-2 : If you want to for some reason preserve the words array, then use

$wordArr = preg_replace("/(.*)/", '/\1', $words);

to convert all words to valid regexes. I think even with this overhead, it should be faster than strstr on a long list.

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