File Uploading with Servlets? [duplicate]

This question already has answers here: How can I upload files to a server using JSP/Servlet? (14 answers) Closed 3 years ago.

Note:

Before reading this question and its answer, please check your in开发者_开发技巧put element has name attribute.

I am trying to upload file using servlet. Eclipse console shows no errors. But the file is not getting uploaded. For me, it seems everything is fine. But I am making mistake somewhere.

In console I get just

Inside Servlet //Printed by code
Items: [] // Printed by Cdoe

Html Code:

<form action="ImageUploadServlet" method="post" enctype="multipart/form-data">
<table>
<tr>
  <td><label>Select Image: </label></td>
  <td><input type="file" id="sourceImage" /></td>
   <tr>
        <td colspan="3">
         <input type="submit" value="Upload"/><span id="result"></span>
        </td>
      </tr> 
</table>
</form>

Servlet Code:

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

    boolean isMultiPart = ServletFileUpload.isMultipartContent(request);
    System.out.println("Inside Servlet");
    if(!isMultiPart){
        System.out.println("Form type is not multipart/form-data");
        System.out.println("File Not Uploaded");
    }
    else
    {
        FileItemFactory dfit = new DiskFileItemFactory();
        ServletFileUpload sfu = new ServletFileUpload(dfit);
        List aList = null;

        try {
            aList = sfu.parseRequest(request);
            System.out.println("Items: "+aList);
        } 
        catch (FileUploadException fue) 
        {
            fue.printStackTrace();
        }

        Iterator itr = aList.iterator();
        while(itr.hasNext())
        {
            FileItem fi = (FileItem) itr.next();
            if(fi.isFormField())
            {
                System.out.println("File Name: "+fi.getFieldName());
                System.out.println("File Size: "+fi.getSize());

                try 
                {
                    File f = new File("D:/MyUploads/", fi.getName());
                    fi.write(f);
                } 
                catch (Exception e) 
                {
                    e.printStackTrace();
                }
            }
            else
            {
                System.out.println("It's Not Form Item;");
            }
        }
    }
}
}

Any suggestions would be appreciated.

Thanks!

---

There are two problems:

First, you need to give the field a name. It becomes then the request parameter name.

<input type="file" id="sourceImage" name="sourceImage" />

Second, you need to handle the file uploads in the else case of FileItem#isFormField() as per the commons fileupload guide. Your code is currently ignoring them and doing only a sysout.

if (item.isFormField()) {
    // Process regular form field (input type="text|radio|checkbox|etc", select, etc).
    String fieldname = item.getFieldName();
    String fieldvalue = item.getString();
    // ... (do your regular form field processing job here)
} else {
    // Process form file field (input type="file").
    String fieldname = item.getFieldName();
    String filename = FilenameUtils.getName(item.getName());
    // ... (do your uploaded file job here)
    File file = new File("D:/MyUploads/", filename);
    item.write(file);
}

Note that you need to use FilenameUtils#getName() to extract the file name, because MSIE browser incorrectly sends the full client side file path along the file name. See also Commons FileUpload FAQ.

You also need to keep in mind that this approach will overwrite any previously uploaded file with the same name. You may want to add an autogenerated suffix to the filename.

See also:

• How to upload files in JSP/Servlet?

---

Maybe this will help:

http://www.theserverside.com/news/1365153/HttpClient-and-FileUpload