$comment = 'billie jean is not my lover she is just a girl';
$words = array('jean','lover','jean');
$lin = some_function_name($comment,$words);
($lin=3)
I tried substr_count()
,开发者_如何学JAVA but it doesn't work on array. Is there a builtin function to do this?
I would use array_filter().
This will work in PHP >= 5.3. For a lower version, you'll need to handle your callback differently.
$lin = sum(array_filter($words, function($word) use ($comment) {return strpos($comment, $word) !== false;}));
This is a simpler approach with more lines of code:
function is_array_in_string($comment, $words)
{
$count = 0;
foreach ($comment as $item)
{
if (strpos($words, $item) !== false)
count++;
}
return $count;
}
array_map would probably produce a much cleaner code.
using array_intersect
& explode
:
to check all there:
count(array_intersect(explode(" ", $comment), $words)) == count($words)
count:
count(array_unique(array_intersect(explode(" ", $comment), $words)))
I wouldn't be surprised if I get downvoted for using regex here, but here's a one-liner route:
$hasword = preg_match('/'.implode('|',array_map('preg_quote', $words)).'/', $comment);
You can do it using a closure (works just with PHP 5.3):
$comment = 'billie jean is not my lover she is just a girl';
$words = array('jean','lover','jean');
$lin = count(array_filter($words,function($word) use ($comment) {return strpos($comment,$word) !== false;}));
Or in a simpler way:
$comment = 'billie jean is not my lover she is just a girl';
$words = array('jean','lover','jean');
$lin = count(array_intersect($words,explode(" ",$comment)));
In the second way it will just return if there's a perfect match between the words, substrings won't be considered.
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