g++ register allocation

Is there a safe way in g++ to force a variable to be in a certain register when a function is called? This function contains inline-asm-code that assumes input开发者_StackOverflow中文版s in certain registers.

I tried to declare local variables to be in fixed registers (register int x asm ("$10")) and pass them to the function, but -O3 messes it up.

I don't want to reserve registers for the whole program by declaring global variables in registers.

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I you want the parameters of a function to be passed in registers, you can do something like this:

int __attribute__((fastcall)) foo(register int a, register int b)
{
    return a + b;
}

• __attribute__((fastcall)) means that the first two parameters of the function are passed in ECX and EDX respectively.
• The register keyword is used to prevent GCC from copying the parameters to the stack once the function is entered.

I found this to work reliably across different -O levels.

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Use asm volatile inline assembly blocks, like explained in this page.

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You can use Extended Assembly. This is for gcc, it should work: http://gcc.gnu.org/onlinedocs/gcc/Extended-Asm.html You can use input register that will be filled by the variable you want. Or you may refer to the C++ variable directly by its name in the inline asm code.

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Pass variables declared with explicit registers directly to the inline asm statement; the register must be specified in the function containing the asm statement.