I have a variable as such:
var is_last = $('.paging a:last').attr('rel');
th开发者_如何学JAVAis returns '-400' which is correct.
However, i need to add 200 to this so the answer is '-200'
if i do this:
var is_last = $('.paging a:last').attr('rel')+200;
the variable is now '-400200'
How can i pass the variable as a value?
A.
You need to parse the output of .attr()
, it to an integer first using parseInt()
so you're dealing with a number (and not a string), like this:
var is_last = parseInt($('.paging a:last').attr('rel'), 10) + 200;
I reckon that @Nick Craver is correct and that parseInt is the more correct answer, but as a quick-and-dirty alternative you can also convince javascript that a variable is a number and not a string by multiplying by 1:
var x = parseInt("-400", 10) + 200;
var y = ("-400" * 1) + 200;
alert(x);
alert(y);
精彩评论