Check if a file is over 30 days old WITHOUT the find command

I've written a bash shell script and part of it is checks if a file is over 30 days old using the find command, sad开发者_JAVA百科ly when I uploaded it to my host it did not work as the find command is locked down.

Does anybody know how to check if a file is over 30 days old WITHOUT the find command?

I'm thinking I need to do an "ls -a $filename" then parse the date string out, convert it to a unix date and then compare it with todays date but I'm very rusty at unix.

Thanks

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stat -c %Z filename gives the last change time in unixtime

stat -c %Y filename if you want the last modification time.

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You can use if [ $file -ot $timestamp_file ] (-ot meaning "older than"). You would have to construct the appropriate file, for example with touch (which takes timestamp options). If this is a periodic task you can also create the timestamp file on each run to use next time.

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Let ls output a unix timestamp, like this:

ls -l --time-style='+%s'

Then get the timestamp from the output, and simlpy calculate whether there are 30 × 24 × 60 × 60 seconds between the current time and the timestamp from ls.

You can get the current timestamp using

date '+%s';

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That doesn't work in Linux: no -v option in date

t=`date +%Y%m%d%H%M`
let u=$t-1000000
touch -t "$u" $DATEFILE
if [ $SERVERFILE -ot $DATEFILE ]; then
  rm $SERVERFILE
fi

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OK this is how I did it in the end...

1. I touched a file with a date of today - 1 month.

touch -t "$(date -v -1m +%Y%m%d%H%M)" ${DATEFILE}

1. Did an older than test on the 2 files.

if [ ${SERVERFILE} -ot ${DATEFILE} ]

Thanks everybody.