I need to overload the << operator for streams to work with built-in types. For strings it's not a problem, since I simply overload the function like this:
ostream& operator<<(ostream& os, const char* str) { /*...*/ }
This works because this function is global, not a member. The problem is that I 开发者_如何学Pythonneed to overload the << operator for other primitive types (ints, floats, etc) but those are member functions. Is there a way I can do this? I need it to work with not only cout but other streams as well. Thanks in advance.
You shouldn't try to change what the operator in std::cout << 3;
does. It's part of a standard API. If you need to output in some format which stream manipulators can't support, then for example you could write a little wrapper:
struct MyFormatter {
MyFormatter (ostream &o) : o(o) {}
ostream &o;
};
MyFormatter &operator<<(MyFormatter &mf, int i) {
mf.o << "int(" << i << ")"; // or whatever
return mf;
}
Then use it like this:
MyFormatter mf(std::cout);
mf << 1 << "," << 2 << "," << 3;
In C++, operator overloads require at least one operand of a "class type" or enumeration type.
The point is you are not allowed to overload operator for primitive types.
http://www.parashift.com/c++-faq-lite/intrinsic-types.html#faq-26.10
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