I'm trying to follow this example http://www.boost.org/doc/libs/1_42_0/libs/serialization/doc/serialization.html#constructors but I ke开发者_JS百科ep getting errors. Following the example, I get an error trying to access a private variable (fair enough):
bs.cpp:10: error: ‘const int my_class::m_attribute’ is private
But, if I add save_construct_data as a friend, I get an ambiguity error:
/usr/include/boost/serialization/serialization.hpp:148: error: call of overloaded ‘save_construct_data(boost::archive::text_oarchive&, const my_class*&, const boost::serialization::version_type&)’ is ambiguous
/usr/include/boost/serialization/serialization.hpp:83: note: candidates are: void boost::serialization::save_construct_data(Archive&, const T*, unsigned int) [with Archive = boost::archive::text_oarchive, T = my_class]
bs.cpp:10: note: void boost::serialization::save_construct_data(Archive&, const my_class*, unsigned int) [with Archive = boost::archive::text_oarchive]
bs.cpp:29: note: void boost::serialization::save_construct_data(Archive&, const my_class*, unsigned int) [with Archive = boost::archive::text_oarchive]
I can move the function definition to the friend declaration, but that's just ugly.
What should I try next?
Thanks, Jayen
save_construct_data has to be declared before it can be friended. Something about being in a different namespace. Like this:
namespace boost { namespace serialization {
template<class Archive>
inline void save_construct_data(Archive & ar, const my_class * t, const unsigned int file_version);
}}
But, because that depends on my_class, you have to declare my_class as well:
class my_class;
So the whole thing looks like http://pastebin.com/embed_iframe.php?i=aFyCpjyY
Make sure the save_construct_data method isn't declared in a different scope besides that from which the boost library calls the methods (boost::serialization)
Declaring the save_construct_data in a custom namespace will cause ambiguity issues as boost won't know which method to call
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