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How do I create a parameter list for a function?

开发者 https://www.devze.com 2023-01-23 20:38 出处:网络
I am creating an array of arrays in the following way: $final_array = array(); for($i = 0; $i < count($elements); $i++) {

I am creating an array of arrays in the following way:

$final_array = array();
for($i = 0; $i < count($elements); $i++) {
    for($j = 0; $j < count($elements); $j++) {
        if($i!=$j)
            $final_array[] = array_intersect($elements[$i], $elements[$j]);
    }
}

I am trying to find out the list of elements that occur in all the arrays inside the $final_array variable. So I was wondering how to pass this to array_intersect function. Can someone tell me how to construct args u开发者_如何学JAVAsing $final_array[0], $final_array[1], ... $final_array[end_value] for array_intersect? Or if there is a better approach for this, that would be great too.

I am looking for a way to construct the following:

array_intersect($final_array[0], $final_array[1], $final_array[2], ...)


Why do you need to do all of this work? Just use call_user_func_array.

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