Providing an instanceable class's method as a function pointer?

Here is what I'd like to do. I have a function pointer which wants a function like this:

void func(int a);

so I have a class:

 class Foo {
    public:
    void func(int a)开发者_高级运维;
    };

    Foo *foo = new Foo;

    something->setFunction(foo->func);

or in my case:

testWidget[count] = new TestWidget;
            testWidget[count]->eventMouseClick.addHandler(testWidget[0]->silly);

But this gives me:

Error 5 error C3867: 'TestWidget::silly': function call missing argument list; use '&TestWidget::silly' to create a pointer to member c:\users\josh\documents\visual studio 2008\projects\agui\alleg_5\main.cpp 190

Is there a way I could make this work without using a static function?

Thanks

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Is there a way I could make this work without using a static function?

No. You can't convert a pointer to member function to an ordinary function pointer.

If the callback accepted any callable object (or a std::function, for example), then you could bind the object to the member function and pass the result of that; unfortunately, you can't convert that result to an ordinary function pointer, though.

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Your question is not very clear to me. But the error message from the compiler makes me feel that probably you want something like this something->setFunction(&foo->func);

An example might help in case of overloads

struct T{
   void func(int){}
   void func(double){}
};


void f(void (T::*f)(int)){}
void f(void (T::*f)(double)){}

int main(){
   void (T::*fi)(int) = &T::func;
   void (T::*fd)(double) = &T::func;

   f(fi);
   f(fd);
}