If there are two branches, and I have been doing work on the default
branch, I think one way to push to the foo
bran开发者_Go百科ch of the other clone is
cd ~/development/clone2
hg up default
hg pull ~/developmet/clone1
hg up foo
hg merge default
or
cd ~/development/clone1
hg up default
hg push ~/developmet/clone2
cd ~/development/clone2
hg up foo
hg merge default
These 2 methods work exactly the same? (one is a pull, one is a push).
Is there an easier way to directly push clone1's default
branch to clone2's foo
branch? thanks.
(I use clone 1 to see all the changes I have done (without seeing anybody else's changes), and use clone2 to merge and integrate with other team members)
You can always push and pull a single revision and all of it ancestors using:
hg push -r revision ~/development/clone1
or
hg pull -r revision ~/development/clone2
There's no way to "push to another branch" because you'll always have to merge the two different branches manually
Both methods you described work exactly the same, but the first one is recommended (Always do the merge work in your clone, not the integration repository or somebody else's clone)
Maybe is an intentional omission but in both examples you have to commit the result of the merge and in the first example you have to push the merge changeset back to clone2
So in ~/development/clone1 do:
hg up default
hg pull -u ~/development/clone2
hg up foo
hg merge default
hg ci -m 'merged default into foo'
hg push ~/development/clone2
If you do this a lot you may consider adding this lines to your ~/development/clone1/.hg/hgrc file
[paths]
default = ~/development/clone2
This way you can omit the repository path when you're pulling and pushing from the integration repository
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