I've got a data frame with 2 character columns. I'd like to find the rows which one column contains the other, however grepl is being strange. Any ideas?
> ( df <- data.frame(letter=c('a','b'),food = c('apple','pear','bun','beets')) )
letter food
1 a apple
2 b 开发者_开发知识库 pear
3 a bun
4 b beets
> grepl(df$letter,df$food)
[1] TRUE TRUE FALSE FALSE
but i want T F F T
Thanks.
Thanks to Kevin's suggestion to use apply,
>
mapply(grepl,df$letter,df$food)
results in the desired output.
When I run your code, I get a warning:
Warning message:
In grepl(df$letter, df$food) :
argument 'pattern' has length > 1 and only the first element will be used
This is confirmed by ?grepl
under pattern
:
If a character vector of length 2 or more is supplied,
the first element is used with a warning.
So grepl is finding the a in both apple and pear. This doesn't solve your problem (apply or one of its variants?), but it does explain the output you are getting.
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