why isnt this php working, i get undefined index...?_问答_开发者

why isnt this php working, i get undefined index...?

开发者 https://www.devze.com 2022-12-10 14:56 出处：网络

I am trying to upload an image to the se开发者_如何学JAVArver. I hava a form with a couple of inputs...

相关专题：javascript php

I am trying to upload an image to the se开发者_如何学JAVArver.

I hava a form with a couple of inputs... INSIDE this form, I have an Iframe which contains another form for the upload, this because I dont want the original form to submit().

The original form basically:

      <form> ...... bla bla bla alot of inputs....<iframe src="pic_upload.html"></iframe></form>

Here is pic_upload.html:

      </head>
      <body><form name="pic_form" id="pic_form" action="bincgi/imageUpload.php" method="post" target="pic_target"><input name="pic_file" type="file" id="pic_file" size="35" onchange="this.form.submit();"></form><div id="pic_target" name="pic_target" style="width:80px; height:80px;"></div></body>
      </html>

Here is imageUpload.php:

      <?php
      $destination_path = getcwd().DIRECTORY_SEPARATOR;
      //echo $destination_path;
      $result = 0;
      $target_path = $destination_path . basename($_FILES['pic_file']['name']);
      if(@move_uploaded_file($_FILES['pic_file']['tmp_name'], $target_path)) {
      $result = 1;
      }
      ?>

I get this error: Undefined index: pic_file on line 5 in imageUpload.php

ALSO, if I get this to work, is there a good way to display the uploaded image inside the target of the form?

Thanks alot! PS: I will add javascript to the tags because maybe thats what I need here!

Don't forget about form attribute

enctype="multipart/form-data"

The form needs to be like this

<form enctype="multipart/form-data" action="__URL__" method="POST">

Check out this PHP.net documentation for more information.

You first need to test if $_FILES has an item with the key pic_file. So use the isset function to do so:

$destination_path = getcwd().DIRECTORY_SEPARATOR;
//echo $destination_path;
$result = 0;
if (isset($_FILES['pic_file'])) {
    $target_path = $destination_path . basename($_FILES['pic_file']['name']);
    if (@move_uploaded_file($_FILES['pic_file']['tmp_name'], $target_path)) {
        $result = 1;
    }
}