I want to remove the following specified characters from a string:
<
&
"
#
%
So something like:
Test%开发者_如何学JAVA#"&<value
should become:
Testvalue
The order of characters is immaterial.
There's something weird about the string type.
A test string looks like this:
var_dump($test): string(25) "A BCDEFG/<&"#%/HI"
The number of characters is NOT adding up to 25 and I'm not sure why.
If I do:
$displayName = strtr($displayName, array('<' => '', '&' => '', '"' => '', '#' => '', '%' => ''));
I get:
string(20) "A BCDEFG/lt;quot;/HI"
Escaping the <
will work:
$displayName = preg_replace('/\<&"#%/', '', $displayName);
However the surrounding /
serve as delimiters for the preg_*
family. Therefore, you must do the following to remove these, too:
$displayName = preg_replace('|/\<&"#%/|', '', $displayName);
(Here I use |
as delimiter instead since this character is not part of the expression itself.)
EDIT
If you're just interested in replacing the characters <
, &
, "
, #
, and %
, this is probably preferable:
$displayName = str_replace(array('<', '&', '"', '#', '%'), '', $displayName);
EDIT 2
A great deal of confusion later, it seems that the $displayName
string did actually contain A BCDEFG/<&"#%/HI
. In that case you could replace the HTML entities directly (untested):
$displayName = str_replace(array('<', '"', '&', '#', '%'), '', $displayName);
If you want to do it with regular expressions:
<?php
$displayName = 'A BCDEFG/<&"#%/HI';
$displayName = preg_replace('/[\<&"#%]/', '', $displayName);
echo($displayName);
?>
This outputs:
A BCDEFG//HI
Regarding the "number of characters not adding up" part: It used to be true that one char was one byte, but you can't count on that any more. My guess is that var_dump() shows how many bytes the string is internally, which you really should not care about.
When working with strings in high-level languages you really should concentrate on number of characters and forget how many bytes a string is. (there are exceptions, of course ;)
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