get some substring from readline() in python with regular expression

I use tcpdump to sniff my network packet and I want to g开发者_StackOverflow社区et some info out of the stored file. My file have 2 separated lines but they repeated many times.

23:30:43.170344 IP (tos 0x0, ttl 64, id 55731, offset 0, flags [DF], proto TCP (6), length 443)

192.168.98.138.49341 > 201.20.49.239.80: Flags [P.], seq 562034569:562034972, ack 364925832, win 5840, length 403

I want to get timestamp(23:30:43.170344) and id(id 55731) and offset(23:30:43.170344) from first line(all line like this on my file). and store in a different list.

And get 2 separated ip (192.168.98.138.49341 and 201.20.49.239.80) and seq (seq 562034569:562034972) and ack(ack 364925832) from the second (all line like this on my file) line and store in a different list.

If I can do this with a regular expression it would be best.

---

For the first portion, to get timestamp, id and offset.

I am sure this is a crude regex.

>>> import re
>>> l = '23:30:43.170344 IP (tos 0x0, ttl 64, id 55731, offset 0, flags [DF], proto TCP (6), length 443)'
>>> k = re.compile(r'^([0-9:]+\.[0-9]+) IP \(.* id ([0-9]+), offset ([0-9]+).*\)')
>>> x = k.match(l)
>>> x.groups()
('23:30:43.170344', '55731', '0')
>>> x.groups()[0]
'23:30:43.170344'
>>> x.groups()[1]
'55731'
>>> x.groups()[2]
'0'
>>> 

For the second part:

>>> l = '192.168.98.138.49341 > 201.20.49.239.80: Flags [P.], seq 562034569:562034972, ack 364925832, win 5840, length 403'
>>> k = re.compile(r'^([0-9.]+) > ([0-9.]+): .* seq ([0-9:]+), ack ([0-9]+).*')
>>> x = k.match(l)
>>> for y in x.groups(): print y
... 
192.168.98.138.49341
201.20.49.239.80
562034569:562034972
364925832

For a read up on re module:

• http://www.doughellmann.com/PyMOTW/re/