I am making game of life in 2D array. I need to determine when all adjacent cells are empty so I just test all of them. It works well unless the cell being checked is the boundary. Then of course testing X+1 throws an exception as the index is out of the array bound开发者_StackOverflow中文版aries. Can I handle this somehow instead of handling the exception? Thanks
use GetLength(0)
and GetLength(1)
to get the width and height of the array.
There is also a neat performance trick the runtime uses for its own bounds checks: casting to unsigned int to reduce the two checks into one. But since this costs readability you use it if the check is really performance critical.
(i >= 0) && (i < length)
becomes
(uint)i < length
If you want speed you'll have to treat the edge-cells differently and process the rest with a
for(int x = 1; x < Size-1; x++) // these all have x-1 and x+1 neighbours
I created an extension method for a 2D array to check if in bounds:
public static class ExtensionMethods
{
public static bool In2DArrayBounds(this object[,] array, int x, int y)
{
if (x < array.GetLowerBound(0) ||
x > array.GetUpperBound(0) ||
y < array.GetLowerBound(1) ||
y > array.GetUpperBound(1)) return false;
return true;
}
}
Yes, before accessing the element at index i + 1
, check whether i + 1
is strictly inferior to array.Length
.
精彩评论