$(function () {
var sr = 'section.row';
var fot = 'figure.one_third';
var pA = 'div.portfolio ul li a';
开发者_JS百科 var item = ('sr fot pA');
$item.addClass('blue');
});
http://jsfiddle.net/G8yJj/13/ <<
the line needs to be:
var item = $(pA);
item.addClass('blue');
or in your updated question:
var item = $(sr + ' ' + fot + ' ' + pA);
if that's what you want.
There's no need for any extra quotes.
Just use var $item = $(pA);
sr and fot are not getting evaluated as variables, they are just part of the string.
You need
$(sr + "," + fot + "," + pA)
As cambraca said in a comment, no quotes.
$(function () {
var pA = 'div.portfolio ul li a';
var $item = $(pA);
$item.addClass('blue');
});
You do write
var $item = $("div.portfolio ul li a");
But thats only because you need to have a way to mark the selector div.portfolio ul li a
as a non-javascript query. If you explicitly make a String with those contents, then quoting it would read like this.
var $item = $('"' . '"div.portfolio ul li a"' .'"');
And, that doesn't make sense.
精彩评论