not understanding why this code is not working_问答_开发者

not understanding why this code is not working

开发者 https://www.devze.com 2022-12-10 14:18 出处：网络

im new to sessions but from what i see it complicated to apply <input> with them.can you please look at this code and tell me why its not working. i had it working earlier then it died on me. th

相关专题：php session

im new to sessions but from what i see it complicated to apply <input> with them. can you please look at this code and tell me why its not working. i had it working earlier then it died on me. the function of the program is to fill out a form and have it verified for legit information using regular expressions, i just need help with getting the sessions to save the data.

<?php session_start(); ?> 
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>regex</开发者_运维技巧title>


</head>

<body>

<?php

$fname = $_REQUEST['fname'];

$fname = $_SESSION['fname'];


print<<<form

<form method="post"  action="">

  <input type ="text"
             name="fname"
             value="">

    <input type ="submit">

</form>

form;

$_SESSION['fname'] = $fname;

 print $_SESSION['fname'];


?>

</body>
</html>

You are reading $fname from $_REQUEST, then overwriting it with the value from $_SESSION, then putting it back to $_SESSION. So far, it should work as designed :) What are you trying to do? If you want to set the $_SESSION variable with the value received through $_REQUEST, leave out the second "$fname=" line.

Timothy, Change your code so that it checks if the session/request is empty or not

Something like:

if(isset($_REQUEST['fname'])){
  $fname = $_REQUEST['fname'];
}else if(isset($_SESSION['fname'])){
  $fname = $_SESSION['fname'];
}

Try this:

if (!isset($_SESSION['fname'])) {
    $_SESSION['fname'] = '';  // default value
}
if (isset($_POST['fname'])) {
    $_SESSION['fname'] = $_POST['fname'];
}

print<<<form

…

form;

print $_SESSION['fname'];