I have a for each with a limit of 3 items to display. The problem is that it if I limit it to 3...it doesn't begin with the first entry as it supposed to do.开发者_开发问答 In stead it starts at the second one. I have my entries ranked from 001 to 020. And I sorted the for-each on this rank. So the first 4 would be displayed. So there should be something wrong with my for-each statements?
<xsl:for-each select="data/activity-feed/entry[recommended = 'Yes'][position() mod 4]">
<xsl:sort select="activity-rank" data-type="number" order="ascending" />
<a href="{$root}/items">
<p>
<xsl:value-of select="activity-name"/>
<xsl:call-template name="description">
</p>
</a>
</xsl:for-each>
My XML:
<data>
<activity-feed>
<entry id="65">
<recommended>Yes</recommended>
<activity-name handle="forra-dive">Forra Dive</activity-name>
<activity-rank handle="001">001</activity-rank>
</entry>
</activity-feed>
</data>
Any idea how to make only the FIRST 4 display? Thanks
I think the problem is that in the for-each select, position()
is evaluated in the unsorted order of the entry. So you're getting the first 3 in the original (document) order instead of in the ranked order. If you show more of your input data we could tell for sure.
If that's the case, try:
<xsl:for-each select="data/activity-feed/entry[recommended = 'Yes']">
<xsl:sort select="activity-rank" data-type="number" order="ascending" />
<xsl:if test="position() < 4">
<a href="{$root}/items">
<p>
<xsl:value-of select="activity-name"/>
<xsl:call-template name="description">
</p>
</a>
</xsl:if>
</xsl:for-each>
The fix is that we're testing for position()
inside the sorted for-each
loop, instead of "outside" the sort.
Why do you use modulus? If you use a static number, the loop limitation should succeed.
<xsl:for-each select="data/activity/entry[recommended='Yes'][position() < 4]>
...
</xsl:for-each>
精彩评论