The syntax for this is:
sed -n '/Regex1/,开发者_开发知识库/Regex2/p'
But this includes the lines where Regex1 and Regex2 are found, how can I exclude them?
For example:
abcd-Regex1
BlaBlaBla
abcd-Regex2
Then I only want: BlaBlaBla
You can do this with a simple state machine in awk
:
pax> echo 'abcd-Regex1
BlaBlaBla
abcd-Regex2' | awk '/Regex2/{e=0}{if(e){print}}/Regex1/{e=1}'
BlaBlaBla
It basically uses an echo flag e
, with the commands below executed in sequence for each line:
/Regex2/{e=0}
turns echo off when terminating line found.{if(e){print}}
prints line if echo is on./Regex1/{e=1}
turns echo on when initialising line found.
If you must use only sed
, there is a way you can do it by passing it through another sed
to delete the start and end lines:
pax> echo 'asdf
abcd-Regex1
BlaBlaBla
abcd-Regex2' | sed -n '/Regex1/,/Regex2/p' | sed -e '/Regex1/d' -e '/Regex2/d'
BlaBlaBla
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