I am trying to figure out how to manage multiple lazy sequences from a single function in F#.
For example, in the code below, I am trying to get two sequences - one that returns all files in the directories, and one that returns a sequence of tuples of any directories that could not be accessed (for example due to permissions) with the exception.
While the below code compiles and runs, errorSeq never has any elements when used by other code, even though I know that UnauthorizedAccess exceptions have occurred.
I am using F# 2.0.
#light
open System.IO
open System
let rec allFiles errorSeq dir =
Seq.append
(try
dir |> Directory.GetFiles
with
e -> Seq.append errorSeq [|(dir, e)|]
|> ignore
[||]
)
(try
dir
|> Directory.GetDirectories
|> Seq.map (allFiles errorSeq)
|> Seq.concat
with
e -> Seq.append errorSeq [|(dir, e)|]
|> ignore
Seq.empty
)
[<EntryPoint>]
let main args =
printfn "Arguments passed to function : %A" args
let errorSeq = Seq.empty
allFiles 开发者_StackOverflow社区errorSeq args.[0]
|> Seq.filter (fun x -> (Path.GetExtension x).ToLowerInvariant() = ".jpg")
|> Seq.iter Console.WriteLine
errorSeq
|> Seq.iter (fun x ->
Console.WriteLine("Error")
x)
0
If you wanted to take a more functional approach, here's one way to do it:
let rec allFiles (errorSeq, fileSeq) dir =
let files, errs =
try
Seq.append (dir |> Directory.GetFiles) fileSeq, errorSeq
with
e -> fileSeq, Seq.append [dir,e] errorSeq
let subdirs, errs =
try
dir |> Directory.GetDirectories, errs
with
e -> [||], Seq.append [dir,e] errs
Seq.fold allFiles (errs, files) subdirs
Now we pass the sequence of errors and the sequence of files into the function each time and return new sequences created by appending to them within the function. I think that the imperative approach is a bit easier to follow in this case, though.
Seq.append
returns a new sequence, so this
Seq.append errorSeq [|(dir, e)|]
|> ignore
[||]
has no effect. Perhaps you want your function to return a tuple of two sequences? Or use some kind of mutable collection to write errors as you encounter them?
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