Given the schema:
Student(Snum, Sname)
Course(Cnum, Cname)
Prerequisite(Cnum, Prereq)
Professor(Pnum,Pname, Dept, Office)
Enrollment(Snum, Cnum, Term, Section, Mark)
Schedule(Cnum, Term, Section, Days, Time, Room)
Class(Cnum, Term, Section, Instructor)
I have come up with:
SELECT * FROM Student s
HAVING MIN(
SELECT COUNT(*) FROM Enrollment e
WHERE e.Snum = s.Snum
GROUP BY e.Term
) > 6
But I am getting:
/* SQL Error (1064): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT COUNT(*) FROM Enrollment e WHERE e.Snum = s.Snum GROUP BY e.Term ) >' at line 3 */
Any idea as to how I can fix this? Thanks!
Also, it would be reassuring to know that I have the right logic =)
EDIT: FINAL ANSWER...
SELECT Student.Sname
FROM(
SELECT COUNT(DISTINCT Cnum) as `classes`, e.Term as `term`, e.Snum as `student`
FROM E开发者_运维技巧nrollment e
GROUP BY e.Term, e.Snum
) x
JOIN Student ON Student.Snum = `student`
WHERE x.`classes` > 6
If you want to see students that had at least 6 classes in each term:
SELECT * FROM Student s
WHERE (SELECT MIN(perTerm) FROM(
SELECT COUNT(DISTINCT Cnum) as perTerm FROM Enrollment e
WHERE e.Snum = s.Snum
GROUP BY e.Term
)) > 6
Here you go. You were almost there, but HAVING
cannot be used if you don't have a GROUP BY
.
If you want any term replace MIN
with MAX
and if you want a specific term use the updated version of Vegard.
If the double subquery doesn't work try this one:
SELECT `student`
FROM(
SELECT COUNT(DISTINCT Cnum) as `classes`, s.Term as `term`, s.Snum as `student`
FROM Enrollment e
GROUP BY e.Term, e.Snum
)
GROUP BY `term`
HAVING MIN(`classes`) > 6
SELECT * FROM Student s
WHERE (
SELECT COUNT(*) FROM Enrollment e
WHERE e.Snum = s.Snum
AND e.Term = <some term>
) > 6
No need to use an aggregate function here, so use a normal WHERE
(not HAVING
) for the subquery as well.
Edit: modified to only check one term at a time. If you absolutely need to check all terms, I don't immediately have a good idea.
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