I've just found some C++ code (at http://msdn.microsoft.com/en-us/library/k8336763(VS.71).aspx), which uses a technique I've never seen before to add types to an existing class:
class Testpm {
public:
void m_func1() { cout << "m_func1\n"; }
int m_num;
};
// Define derived types pmfn and pmd.
// These types are pointers to members m_func1() and m_num, respectively.
void (Testpm::*pmfn)() = &Testpm::m_func1;
int Testpm::*pmd = &Testpm::m_num;
int main() {
Testpm ATestpm;
Testpm *pTestpm = new Testpm;
// Access the member function
(ATestpm.*pmfn)();
(pTestpm->*pmfn)(); // Parentheses required since * binds
// Access the member data
ATestpm.*pmd = 1;
pTestpm->*pmd = 2;
cout << 开发者_如何转开发ATestpm.*pmd << endl
<< pTestpm->*pmd << endl;
}
Can someone please tell me what this technique for defining derived types is called, or point me to some documentation on it? I've never come across it in 13 years of using C++, and would like to end my ignorance.
The comment is incorrect: pmfn and pmd are not "derived types" at all (they are not even types!). They are pointers to members.
I don't think they're "adding types" to the class. They seem to be just defining types of pointers to member functions and member data of the class, and then using those to access the member function and data member. Similar to how you'd declare types to non-member functions, but being members of the class the syntax differs.
From this site here
Regarding their syntax, there are two different types of function pointers: On the one hand there are pointers to ordinary C functions or to static C++ member functions. On the other hand there are pointers to non-static C++ member functions. The basic difference is that all pointers to non-static member functions need a hidden argument: The this-pointer to an instance of the class. Always keep in mind: These two types of function pointers are incompatible with each other.
精彩评论