Understanding __call__ and list.sort(key)

I have the following code I am trying to understand:

>>> class DistanceFrom(object):
        def __init__(self, origin):
            self.origin = origin
        def __call__(self, x):
            return abs(x - self.origin)  

>>> nums = [1, 37, 42, 101, 13, 9, -20]
>>> nums.sort(key=DistanceFrom(10))
>>> nums
[9, 13, 1, 37, -20, 42, 101]

Can anyone explain how this works? As far as I ha开发者_JS百科ve understood, __call__ is what is called when object() is called - calling the object as a function.

What I don't understand is how nums.sort(key=DistanceFrom(10)). How does this work? Can anyone please explain this line?

Thanks!

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__call__ in python allows a class to be run as if it's a function. You can try this out manually:

>>> dis = DistanceFrom(10)
>>> print dis(10), dis(5), dis(0)
0 5 10
>>> 

What sort does is call that function for every item in your list and uses the returned value as sort key. In this example you'll get a list back with the items closest to 10 first, and the one further away more towards the end.

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Here I have defined a function DistanceFrom() which can be used in a similar way to your class, but might be easier to follow

>>> def DistanceFrom(origin):
...     def f(x):
...         retval = abs(x - origin)
...         print "f(%s) = %s"%(x, retval)
...         return retval
...     return f
... 
>>> nums = [1, 37, 42, 101, 13, 9, -20]
>>> nums.sort(key=DistanceFrom(10))
f(1) = 9
f(37) = 27
f(42) = 32
f(101) = 91
f(13) = 3
f(9) = 1
f(-20) = 30
>>> nums
[9, 13, 1, 37, -20, 42, 101]

So you see that the object returned by DistanceFrom is called once for each item of nums and then nums is returned sorted in accordance with the returned values

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It sorts list nums in place using a key function object DistanceFrom(10). It needs to be callable because key needs to be callable. The resulting output is sorted by their "remoteness" from 10, that is 9 is the closest value to 10, 101 is the farthest one.

After the object is initialised and passed as a key parameter to the sort method, on each iteration it will be called with the current value (that's what x is) and returned value would be used to determine x's position in the resulting list.

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When you call something that means you are expecting it to return a value. When you create a class that has the __call__ method defined, you are dictating that an instance of that class can behave as a function does.

For the purpose of this question, this:

class DistanceFrom(object):
        def __init__(self, origin):
            self.origin = origin
        def __call__(self, x):
            return abs(x - self.origin) 

Is functionally equivalent to:

def distance_from(origin, other):
    return abs(other - origin)

As for the key argument to sort, here is your explanation straight from the Python documentation:

key specifies a function of one argument that is used to extract a comparison key from each list element: key=str.lower. The default value is None (compare the elements directly)

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The Python docs are quite good whenever I find I don't understand the fundamentals. I located these with google.

The key parameter is a function that sort will call on the elements of the list. I located this doc by googling sort site:http://docs.python.org/ and then searching for key=.

__call__ is a function you can add to an object to make that object callable as if it were a function. I found this doc by googling __call__ site:http://docs.python.org/ and then following the link to the doc for __call__.