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Joining each item of an array with the items of another array

开发者 https://www.devze.com 2022-12-10 12:45 出处:网络
Consider this: [ [\"a\", \"b\"], [\"c\", \"d\"], [\"e\"] ] How can this be tranf开发者_JAVA技巧ormed to:

Consider this:

[ ["a", "b"], ["c", "d"], ["e"] ] 

How can this be tranf开发者_JAVA技巧ormed to:

[ "a c e", "a d e", "b c e", "b d e" ]


// edit: tested and works

function product(set) {
    if(set.length < 2)
        return set[0];
    var head = set.shift(), p = product(set), r = [];
    for(var j = 0; j < head.length; j++)
        for(var i = 0; i < p.length; i++)
            r.push([head[j]].concat(p[i]));
    return r;
}

var set = [
    [ "a", "b", "c"],
    [ "D", "E" ], 
    [ "x" ]
];

var p = product(set);
for(var i = 0; i < p.length; i++)
    document.write(p[i] + "<br>");


This works:

<html><body><script>
var to_join = [ ["a", "b"], ["c", "d"], ["e"] ];
var joined = to_join[0];
for (var i = 1; i < to_join.length; i++) {
    var next = new Array ();
    var ends = to_join[i];
    for (var j = 0; j < ends.length; j++) {
        for (var k = 0; k < joined.length; k++) {
            next.push (joined[k]+ " " + (ends[j]));
        }
    }
    joined = next;
}
alert (joined);
</script></body></html>


Try concat method:

var newArr=[];

for(var i=0; i< arr.length; i++)
{ 
   newArr = newArr.concat(arr[i]);
}
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