Printing first four lines per key

I would like to print the first 4 lines by field 1 using awk

Input

111 1032192

111 2323476

111 1698881

111 2451712

111 2013780

112 2331004

112 1886376

112 1189765

112 1877267

开发者_StackOverflow中文版

Output

111 1032192

111 2323476

111 1698881

111 2451712

112 2331004

112 1886376

112 1189765

112 1877267

Thanks

Tony

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awk '++count[$1] <= 4' input_file

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($1 != curkey) { curkey=$1; i=0; }
(i < 4)        { i++; print; }