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Lemon Parser-Generator: Are nonterminals not evaluated?

开发者 https://www.devze.com 2023-01-21 20:19 出处:网络
I try to learn parsers. Because my C skills are pretty low, I googled a PHP Lemon to learn sth about Parser Generators. Anyway, the code here should be readable for normal lemon friends, too.

I try to learn parsers. Because my C skills are pretty low, I googled a PHP Lemon to learn sth about Parser Generators. Anyway, the code here should be readable for normal lemon friends, too.

As always when handling parsing questions, I start with trying to produce a simple calculator first.

So my first step is simply this:

start(A)   ::= expr(B). {echo "======RESULT:".A.":".B.":=========".PHP_EOL;}

what parses the first test:

include "mysimple.php"; //include the generated Parser
$P = new ParseParser(); //create a Parser object
$P->Parse(ParseParser::VALUE,"13"); // here is the simple test, just understand the开发者_StackOverflow社区 Number 13, pls
$P->Parse(0,0); //input is finished, parse!
echo "finished. yeah!".PHP_EOL;

...to the result of:

======RESULT:13:=========
finished. yeah!

So, everything as expected. Now we try to prepare a step that finally will allow us to handle operations, the expression:

start ::= expr(B).  {echo "======RESULT:".B.":=========".PHP_EOL;}
expr  ::= VALUE(B). {echo "got a value:".B.PHP_EOL;}

When I run the same test now, I expect to see the same output, plus one line saying got a value: 13. But I just get this:

got a value:13
======RESULT::=========
finished. yeah!

Well, what happened? Why is the result line empty? Obviously expr evaluates to a VALUE of `13'. Does Lemon not care about evaluating? Do I have to do that myself somehow? But how, if I get nothing in this point?


Do you not want something like:

expr(A) ::= VALUE(B). {A = B; echo "got a value:".B.PHP_EOL;}
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