The simple query below is not returning any results. I can't see any errors in it. Any idea why it's not wo开发者_开发技巧rking?
$sqlStr3 = "SELECT loginid,
username,
created
FROM login
ORDER BY created DESC
LIMIT 200";
$result = mysql_query($sqlStr3);
$count = 1;
$arr = array();
echo "<table class=\"samplesrec1edit\">";
while ($row = mysql_fetch_array($result)) {
$dt = new DateTime($row["created"], $tzFrom);
$dt->setTimezone($tzTo);
echo '<tr>';
echo '<td class="sitename1edit2a">'.$count++.'.</td>';
echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>';
echo '<td class="sitename1edit2">'.$dt->format('F j, Y &\nb\sp &\nb\sp g:i a').'</td>';
echo '</tr>';
}
echo "</table>";
Change your query line from:
$result = mysql_query($sqlStr3);
to
$result = mysql_query($sqlStr3) or die("MySQL error: " . mysql_error());
Even if the query itself looks fine, there's a few bazillion reasons something else can be causing problems.
And if it's not already on, please turn on PHP's display_errors and do error_reporting(E_ALL)
. Maybe the query portions are fine and something else is blowing up (eg. a invalid value in $tzFrom
).
精彩评论