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How To (Effectively) use jQuery to Match the Value of an Input with a Database?

开发者 https://www.devze.com 2023-01-21 09:30 出处:网络
I\'ve been working on a PHP project of mine, and I am attempting to add a feature that tells the user whether or not the username they entered in a register form is already taken as they update the in

I've been working on a PHP project of mine, and I am attempting to add a feature that tells the user whether or not the username they entered in a register form is already taken as they update the input. When starting this, I thought I knew how to code this- but I ran into some problems along the way.

When I post the data to my PHP script, I get the 'all clear'. I've double checked it, as well as FireBugged the post- all variables are present, and the server returns exactly as expected. I've inserted a test field into my database so I can see if it works. The name in the DB is 'Cameron'.

Now, for my code.

function checkUsername() {
    $.post(rootpath + "/inc/php/handlers/checkusername.php", {
        submit: "submitted",
     开发者_高级运维   username: $('#username').val()
    }, function (data) {
        if (data = 'not_taken') {

            $('#cui').html('<img src="' + rootpath + '/inc/images/icons/Checkmark-32.png" />');
        }
        else {
            $('#cui').html('<img src="' + rootpath + '/inc/images/icons/block-icon-32.png" width="32" height="32" />');
        }
    }, "html");
}

and then

<input type='text' name='username' id='username' onkeyup='checkUsername();' />

In this case, I was hoping to change the HTML of a div to that of an image. But what the code does is switch to the checkmark image (the first one), regardless of the return (see below).

How To (Effectively) use jQuery to Match the Value of an Input with a Database?

I believed this was a problem with the method I used for updating the div, .html(). But I then discovered that, even if the first combination submitted was that of the database (returning 'taken'), the output would still be the check-mark image.

I need the image to update with, obviously, the correct one. I'm pretty sure it's not a PHP problem as the script I set up returns the data expected.

Thanks in advance for any help!


You're using the assignment operator instead of checking for equality in your conditional:

if(data = 'not_taken') {

should be

if(data == 'not_taken') {


function doAjaxPost(username)
      { 

        var username= $('#username').val();


        $.ajax({  
           type: "POST",  
            url: "/inc/php/handlers/checkusername.php",  
            data: "username="+username+,   
            success: function(resp){  
             //alert($Msg);   
    },  
         error: function(e){  
            //alert($Msg);  
  }  
 });  
 }

in checkusername.php

$SelectQuery=" select usename from userswhere usename='".$_POST['usename']."' ";
                    if($Row=$DB->Select($SelectQuery,'select_capacity',$Module))
                    {
                      $select_record=1;
                    }
                    $sbval=mysql_num_rows($Row);
                    if($sbval>=1)
                    return  "alreay exist";

It will be done in this way . show finel returned message in response div.

It's a way to do. Please change the code according to ur CMS ,architecture,framework.

I hope it will help u. cheers :)

enter code here
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